0=20x^2+6x-8

Solution for 0=20x^2+6x-8 equation:

0=20x^2+6x-8

We move all terms to the left:

0-(20x^2+6x-8)=0

We add all the numbers together, and all the variables

-(20x^2+6x-8)=0

We get rid of parentheses

-20x^2-6x+8=0

a = -20; b = -6; c = +8;
Δ = b2-4ac
Δ = -62-4·(-20)·8
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*-20}=\frac{-20}{-40}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*-20}=\frac{32}{-40}
=-4/5
$